(7/x^2-36)-(1/x-6)

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Solution for (7/x^2-36)-(1/x-6) equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

7/(x^2)-(1/x)-36+6 = 0

7/(x^2)-x^-1-36+6 = 0

7*x^-2-x^-1-30 = 0

t_1 = x^-1

7*t_1^2-1*t_1^1-30 = 0

7*t_1^2-t_1-30 = 0

DELTA = (-1)^2-(-30*4*7)

DELTA = 841

DELTA > 0

t_1 = (841^(1/2)+1)/(2*7) or t_1 = (1-841^(1/2))/(2*7)

t_1 = 15/7 or t_1 = -2

t_1 = -2

x^-1+2 = 0

1*x^-1 = -2 // : 1

x^-1 = -2

-1 < 0

1/(x^1) = -2 // * x^1

1 = -2*x^1 // : -2

-1/2 = x^1

x = -1/2

t_1 = 15/7

x^-1-15/7 = 0

1*x^-1 = 15/7 // : 1

x^-1 = 15/7

-1 < 0

1/(x^1) = 15/7 // * x^1

1 = 15/7*x^1 // : 15/7

7/15 = x^1

x = 7/15

x in { -1/2, 7/15 }

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